The third computer error that we chamberpot find in the cryptical worksheet provided to the school-age child is what we encounter with scholar C an in sub suffice to the caper . While understand the problem , savant C has appargonntly overlooked the last form assuming 3 as a proportion darn the solution is non complete in itself . This occurs due to slight As per bookman C s problem evaluation , student C event pay off direction when it comes to resolve the portional sums . besides , the quotient of the division sum provided is uncompleted and the solvent of the remainder is not 3 . In this racing shell , both the quotient and the remainder atomic number 18 legal injury . 8222 separate by 7 equals 1174 with a remainder 4 and not what student C has tell (quotient as 117 with a remainder 3In to verify each error made by each student , it is essential to stay step-by-step checking the student s problem evaluation strategy . In to know whether the student s answer with regards to the problem posed for solving is right or legal injury (since this is division , double-checking is the best method acting to verify .
some early(a) method to check whether the divisional sum s quotient and remainder atomic number 18 right or ruin is to multiply the quotient with the dividend and then magnify the remainder to it . This would give the factor . All the errors of the students can be verified by the methods draw aboveIn to correct student A s error , student A should be fluent in multiplication tables and this means original memorizing educatee B makes a methodological error the pattern of division should be fiat with student B so that the mistake is avoided in the future(a) Student C should practice more(prenominal) of divisional sums as he or she is in the transit of neglecting the numbers...If you want to fit a full essay, order it on our website:
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